Project Euler Problem #6 - Sum Square Difference (in Java)

  1. public class Problem_6_Sum_Square_Difference {

  3.     /*
  4.         The sum of the squares of the first ten natural numbers is,
  5.         12 + 22 + ... + 102 = 385
  6.                 
  7.         The square of the sum of the first ten natural numbers is,
  8.         (1 + 2 + ... + 10)2 = 552 = 3025
  9.                 
  10.         Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 - 385 = 2640.

  12.         Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
  13.     */
  14.         
  15.     public static void main (String[] args) {
  16.                 
  17.         int sumSquares = 0, sum = 0, difference = 0;
  18.                 
  19.         for (int i = 1; i <= 100; i++) {
  20.             sum += i;
  21.             sumSquares += (int)Math.pow(i, 2);
  22.         }
  23.                 
  24.         difference = (int)Math.pow(sum, 2) - sumSquares;
  25.         System.out.println(difference);
  26.     }
  27. }
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              Created: February 10, 2014
Completed in full by: Michael Yaworski